CBSE Class 9 Maths Lab Manual – Mid-point Theorem

CBSE Class 9 Maths Lab Manual – Mid-point Theorem

Objective
To verify that in a triangle, the line joining the mid-points of any two sides is parallel to the third side and half of it by paper folding and pasting.

Prerequisite Knowledge

  1. Concept of angles, triangles and mid-points.
  2. Concept of corresponding angles: If a transversal cuts two straight lines such that their corresponding angles are equal, then the lines are parallel.

Materials Required
Glazed papers, a pair of scissors, pencil, eraser, gluestick, white sheet.

Procedure

  1. Draw ∆ABC on the yellow glazed paper of any measurement and paste it on white sheet.
  2. Find mid-points of the two sides (say AB and AC) of a triangle by paper folding. We obtain D and E as mid-points of AB and AC respectively in 1st triangle.
    CBSE Class 9 Maths Lab Manual – Mid-point Theorem 1
  3. Draw horizontal line DE. Similarly find mid-point of side BC and name it F as shown in fig. (ii).
    CBSE Class 9 Maths Lab Manual – Mid-point Theorem 2
  4. Trace the ∆ABC on tracing paper and cut ∆ABC along line DE as shown in fig.(iii).
    CBSE Class 9 Maths Lab Manual – Mid-point Theorem 3
  5. Paste this cut out of triangle ADE [fig. (iii) ] on ∆ABC of fig. (ii) such that AE coincides with EC and ED lies on CB and point D coincides with F as shown in fig. (iv).
    CBSE Class 9 Maths Lab Manual – Mid-point Theorem 4
  6. ∆ADE completely covers ∆EFC.

Observation
We observe that ∆ADE exacdy overlaps ∆EFC.
∴ ∠1 = ∠2 (corresponding angles)
AC is any transversal line intersecting the lines DE and BC.
∴ DE || BC.
By paper folding we observe that, in fig (iv) F, the mid point of BC coincides with D.
∴ DE = FC (As DE superimposes on FC)
or DE = FC = \(\frac { BC }{ 2 }\)

Result
Hence, it is verified that the line joining the mid-points of two sides of a triangle is parallel to third side and half of it.

Learning Outcome
Line segment joining the mid-points of any two sides of a triangle is parallel to the third side and is equal to half of it. This is true for all types of triangles like acute-angled triangle, obtuse-angled triangle and right-angled triangle.

Activity Time
Students can verify this theorem in different triangles, e.g., obtuse-angled triangle, right-angled triangle, equilateral triangles, scalene triangles.

Viva Voce

Question 1.
State the mid-point theorem.
Answer:
The line drawn through the mid-point of one side of a triangle and parallel to another side of the triangle, bisects the third side of the triangle.

Question 2.
What is the area of a triangle ?
Answer:
Area of triangle = \(\frac { 1 }{ 2 }\) x base x height

Question 3.
Name the different triangles on the basis of its sides.
Answer:
Equilateral triangle, scalene triangle, isosceles triangle.

Question 4.
Name the different triangles on the basis of its angles.
Answer:
Acute angled triangle, obtuse angled triangle and right angled triangle.

Question 5.
Is mid-point theorem applicable in any type of triangle ?
Answer:
Yes.

Question 6.
In a triangle, the line drawn through the mid-point of one side is parallel to another side, what is the ratio of parallel line to the third side ?
Answer:
1:2.

Question 7.
In a triangle, the line drawn through the mid-points of two sides, then what will be the relation between the line and the third side ?
Answer:
Line will be parallel to the third side.

Question 8.
In a ∆ABC, D, E, F are the mid-points of the sides BC, CA and AB respectively, and ∠BAC = 70°, what is the value of ∠EDF?
Answer:
70°

Multiple Choice Questions

Question 1.
In a ∆ABC, P is the mid-point of AB and Q is mid-point of AC and PQ = 4 cm, what will be the length of BC?
(i) 8 cm
(ii) 16 cm
(iii) 2 cm
(iv) none of these

Question 2.
In a right-triangle PQR, A is the mid-point of PQ and B is the mid-point of QR with AB = 5 cm, what will be the length of the hypotenuse PR:
(i) 10 cm
(ii) 25 cm
(iii) 125 cm
(iv) none of these

Question 3.
What is the length of PB, if in a triangle PQR, if A is the mid-point of PR and AB || QR, and PQ = 6 cm ?
(i) 3 cm
(ii) 12 cm
(iii) 18 cm
(iv) none of these

Question 4.
What is the length of AB, if M is the mid-point of AC and LM || BC, in a ∆ABC ?
(i) 2BM
(ii) 2BL
(iii) \(\frac { 1 }{ 2 }\) AB
(iv) none of these

Question 5.
What will be the length of AC, if L is the mid-point of AB and LM || BC, in ∆ABC and AM = 4 cm ?
(i) 8 cm
(ii) 2 cm
(iii) 9 cm
(iv) none of these

Question 6.
In a right-triangle, mid-points of corresponding sides are joined, the resulting triangle will be:
(i) an acute angled triangle
(ii) an obtuse angled triangle
(iii) a right-angled triangle
(iv) none of these

Question 7.
L, M, N are the mid-points of corresponding sides AB, BC, CA in ∆ABC, the figure so obtained BLMN will be:
(i) parallelogram
(ii) trapezium
(iii) quadrilateral
(iv) none of these

Question 8.
In a right-angled triangle PQR, right angled at ∠Q, A, B and C are mid-points of corresponding sides PQ, QR and PR. The figure so obtained ACBQ is a
(i) parallelogram
(ii) rectanlge
(iii) trapezium
(iv) none of these

Question 9.
In a ∆ABC, P, Q and R are the mid-points of corresponding sides AB, BC and CA. Join P, Q and R. Now ar (∆PQR) will be :
(i) \(\frac { 1 }{ 4 }\) ar(∆ABC)
(ii) \(\frac { 1 }{ 2 }\) ar(∆ABC)
(iii) 4 ar(∆ABC)
(iv) none of these

Question 10.
In a ∆PQR, if B and C are the mid-points of sides PR and QR respectively, then BC || PQ and:
(i) BC = \(\frac { 1 }{ 2 }\) PQ
(ii) BC = 2PQ
(iii) BC = \(\frac { 1 }{ 4 }\) PQ
(iv) none of these

Answers

  1. (i)
  2. (i)
  3. (i)
  4. (ii)
  5. (i)
  6. (iii)
  7. (i)
  8. (ii)
  9. (i)
  10. (i)

Math Lab ManualMath Labs with ActivityMath LabsScience LabsScience Practical Skills

CBSE Previous Year Solved Papers Class 12 Computer Science Outside Delhi 2012

CBSE Previous Year Solved  Papers  Class 12 Computer Science Outside Delhi 2012

Time allowed : 3 hours                                                                                           Maximum Marks: 70

General Instructions :

  1.  There are a total of 26 questions and five sections in the question paper, All questions are compulsory.
  2. Section A contains question number 1 to 5, Very Short Answer type questions of one mark each.
  3.  Section B contains question number 6 to 10, Short Answer type I questions of two marks each.
  4.  Section C contains question number 11 to 22, Short Answer type II questions of three marks each.
  5.  Section D contains question number 23, Value Based Question of four marks.
  6. Section E contains question number 24 to 26, Long Answer type questions of five marks each.
  7. There is no overall choice in the question paper, however, an internal choice is provided in one question of two marks, one question of three marks and all three questions of five marks. An examined is to attempt any one of the questions out of two given in the question paper with the same question number.

Question.1.(a) Give the difference between the type casting and automatic type conversion. Also, give a suitable C++ code to illustrate both.
Answer:
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1(b)Which C++ header file(s) are essentially required to be included to run/execute the following C++ source code(Note: Do not include any header file, which is/are not required) :
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Answer:
(iv) iostream.h
(v) string.h
1(c) Rewrite the following program after removing the syntactical error(s) (if any). Underline each correction.
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-3
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-4
Answer:
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-5
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-6
1 (d) Find the output of the following program :
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-7
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-8
Answer:
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-9
1(e) Find the output of the following program :
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-10
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-11
Answer:
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-12
1(f) Observe the following program and find out, which output(s) out of(i) to(iv) will not be expected from the program? What will be the minimum and the maximum value assigned to the variable chance?
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-13
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-14

Question.2.(a) What is the difference between the members in private visibility mode and the members in protected visibility mode inside a class ? Also, give a suitable C++ code to illustrate both.
Answer:
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-15
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-16
2. (b) Answer the question (i) and (ii) after going through the following class.
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-17
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-18

  1.  In Object Oriented Programming, what are Function 1 and Function 4 combined together referred as?
  2.  In Object Oriented Programming, which concept is illustrated by Function 3? When is this function called/ invoked?

Answer:

  1.  Polymorphism OR Constructor Overloading
  2.  Function 3: Destructor ‘
    A destructor called/invoked when an object of that class is destroyed. When a variable goes out of scope, or a dynamically allocated variable is explicitly deleted using the delete keyword, the class destructor is called to help clean up the class before it is removed from memory.

2. (c) Define a class RESTRA in C++ with following description: Private Members:

  • FoodCode of type int
  •  Food of type string
  •  FType of type string
  •  Sticker of type string
  • A member function GetSticker() to assign the following values for Sticker as per the given Ftype
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Public Members:

  •  A function GetFoodO to allow user to enter values for FoodCode, Food,Ftype and call function „ GetSticker( ) to assign Sticker.
  •  A function ShowFoodO to allow user to view the concept of all the data members.

Answer:
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-20
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-21
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-22
2. (d) Answer the questions (i) to (iv) based on the following :
class COMPANY
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-23
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-24
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-25

  1.  Name the type of inheritance illustrated in the above C++ code.
  2.  Write the names of data members, which are accessible from member functions of class SHOP.
  3.  Write the names of all the member functions, which are accessible from objects belonging to class FACTORY.
  4.  Write the names of all the members, which are accessible from objects of class SHOP.

Answer:

  1. Hierarchical Inheritance
  2.  None of the data members can be accessible except SHOP class data members.
  3.  Register!),Enter!) and Show( ) of Factory class.
  4.  Input! ( ) Output!( )

Question.3. (a) Write a function SWAP2BEST (int ARR[],int Size) in C++ to modify the content of the array in such a way that the elements, which are multiples of 10 swap with the value present in the very next position in the array.
For example
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-26
Answer:
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-27
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-28
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-29
3. (b) An arrayT[20][10] is stored in the memory along the column with each of the element occupying 2 bytes, find out the memory location of T[10] [5],if an element T[2] [9] is stored at location7600.
Answer:
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-30
3. (c) Write a function in C++ to perform insert operation in a static circular Queue containing Book’s information (represented with the help of an array of structure BOOK).
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-31
Answer:
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-32
3. (d) Write a function ALTERNATE (int A[][3],int N,int M) in C++ to display all alternate element from two¬dimensional array A (starting from A[0] [0]).
For example:
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-33
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-34
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-35
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-36
(e) Evaluate the following POSTFIX notation. Show status of stack after every step of evaluation (i.e. after each operator):
True, False, NOT, AND, False, True, OR, AND
Answer:
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Question.4. (a)Student try to answer this question Observe the program segment given below carefully and the question that follow:
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cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-41

  1. Write statement 1 to position the file pointer to the appropriate place, so that the data updation is done for the required item.
  2.  Write statement 2 to perform the write operation so that the updation is done in the binary file.

Answer :
Statement 1 – File.seekp(Success);
Statement 2 – File.write((char*) &S, sizeof(S));
(b) Write a function in C++ to read the content of a text file “DELHI.TXT” and display all those lines on screen, which are either starting with ‘D’ or starting With ‘M’
Answer.
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-42
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-43
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-44
(c) Write a function in C++ to search for the details (Phoneno and Calls) of those Phones, which have more , than 800 calls from a binary file “phones.dat”. Assuming that this binary file contains records/objects of class Phone, which is defined below.
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-45
Answer:
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-46

Question.5. (a) Give a suitable example of a table with sample data and illustrate Primary and Alternate Keys in it.
Answer : Primary Key : Primary key is a set of one or more fields/columns of a table that uniquely identify a record in database table. It cannot accept null, duplicate values. Only one candidate key can be primary key.
Alternate key : Alternate key is a key that can be work as a primary key. Basically it is a Candidate key that currently is not primary key.
Example : In below table Admission No. becomes Alternate Keys when we define Registration No. as Primary Key.
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-47
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-48
(b) Write SQL commands for the following statements :

  1.  To display the names of all the silver colored Cars.
  2. To display name of car, make and capacity of cars in
    descending order of their sitting capacity.
  3. To display the highest charges at which a vehicle can be hired from CARDEN.
  4. To display the customer name and the corresponding name of the cars hired by them.

Answer:

  1. SELECT CarName FROM carden WHERE Color = ‘Silver’;
  2.  SELECT CarName,Make,Capacity FROM carden ORDER BY Capacity DESC;
  3. SELECT MAX(Charges) FROM carden;
  4. SELECT Cname,CarName FROM carden,customer WHERE

carden. Ccode=customer.Ccode;

(c) Give the output of the following SQL queries :
(i) SELECT COUNT (DISTINCT Make) FROM CARDEN;
(ii) SELECT MAX(Charges),MIN(Charges) FROM CARDEN;
(iii) SELECT COUNT (*) ,Make FROM CARDEN;
(iv) SELECT CarName FROM CARDEN WHERE Capacity=4;
Answer:
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Question.6.(a) Verify the following using truth table :
(i) X.XN0
(ii)X+l=l
Answer:
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(b) Write the equivalent Boolean Expression for the following Logic Circuit:
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(c)Write the SOP form of a Boolean .Function F, which is represented in a truth table as follows :
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(d) Reduce the following Boolean Expression using K-Map :
F(A,B,C,D) =∑(2,3,4,5,6,7,8,10,11)
Answer:
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Question.7.(a) What out of the following, Svill you use to have an audio-visual chat with an expert sitting in a far-away place to fix-up a technical issue?
(i) VoIP
(ii)email
(iii)FTP
Answer: (i) VoIP
(b) Name one server side scripting language and one client side scripting language.
Answer:

  •  Client side script:
    (a) Javascript
  • server side script:
    (a) ASP

(c)Which out of the following comes under Cyber Crime?

  1. Operating someone’s internet banking account, without his knowledge.
  2. Stealing a keyboard from someone’s computer.
  3. Working on someone’s computer with his/her permission.

Answer:

  1. Operating someone’s internet banking account, without his knowledge.
    (d) Write one advantage of bus topology of network. Also, illustrate how 4 computers can be connected with each other using star topology of network.
    Answer:
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(e) Workalot consultants are setting up a secured network for their office campus at Gurgaon for their day- to-day office and web-based activities. They are planning to have connectivity between 3 buildings and the head office situated in Mumbai. Answer the questions (i) to(iv) after going through the building positions in the campus and other details, which are given below :
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  1. Suggest the most suitable place (i.e. building) to house the server of this organization. Also give a reason to justify your suggested location.
  2. Suggest a cable layout of connection between the buildings inside the campus.
  3. Suggest the placement of the following device with justification:
    (1) Switch
    (2) Repeater
  4. The organization is planning to provide a high speed link with its head office situated in MUMBAI using a wired connection. Which of the following cables will be most suitable for this job?
    (1) Optical Fiber
    (2) Co-axial Cable
    (3) Ethernet Cable

Answer: (i)
RED building because maximum number of computers are there
OR
BLUE building because closest to all other building (minimum cable length required)
Answer: (ii)
cbse-previous-year-solved-papers-class-12-computer-science-outside-delhi-2012-57
Answer: (iii)
Switch. By using 1 switch per building we can use maximum numbers of computers to connect them in network.
Answer : (iv) Optical Fiber
(f) Give one suitable example of each URL and Domain Name.
Answer: URL – http://www.cbsecsnip.in/index.php Domain – cbsecsnip
(g) Name two Proprietary software along with their application.
Answer:
(i) Microsoft Office : Microsoft Office belongs to Microsoft Corporation. This software is used for office automation and also can be used other than office productivity at personal level. Microsoft Office contains following other applications like Microsoft Word, Microsoft Excel, Microsoft PowerPoint, etc.
(ii)Oracle : Oracle Corporation is the owner of Oracle software. Oracle is one of most popular RDBMS software in world.

CBSE Class 10 Science Practical Skills – Types of Reactions

CBSE Class 10 Science Practical Skills – Types of Reactions

Basic Building Concepts
A chemical reaction is a chemical transformation or change in which one or more substances called the reactants are converted to one or more different substances called the products.

Types of Chemical Reactions
There are four types of chemical reactions:

  1. Combination Reactions: Combination reactions are those reactions in which two or more elements or compounds combine to form a more complex compound.
    CBSE Class 10 Science Practical Skills – Types of Reactions 1
  2. Decomposition Reactions: Decomposition reactions are those reactions in which a single compound breaks down into its components or simpler compounds.
    CBSE Class 10 Science Practical Skills – Types of Reactions 2
  3. Displacement Reactions: Displacement reactions are those reactions in which more reactive element takes up the place of another element in a compound and sets the less reactive one free.
    CBSE Class 10 Science Practical Skills – Types of Reactions 3
    You can also download NCERT Solutions Class 10 Science to help you to revise complete syllabus and score more marks in your examinations.The reactivity of metals depends upon the tendency to lose electrons. The more the tendency of a metal to lose an electron, the more will be its reactivity. Non-metals react by gaining electrons. The more the tendency of a non-metal to gain an electron, the more reactive is the non-metal.
  4. Double Displacement Reactions: In a double displacement reaction, ions of two compounds switch places to form two new compounds. Two reactants yield two products.
    CBSE Class 10 Science Practical Skills – Types of Reactions 4

EXPERIMENT 3(a)

Aim  
To perform and observe the action of water on quicklime and classify the reaction.

Materials Required 
Calcium oxide, water, beaker, glass rod, dropper, red litmus paper, test tube, filter paper, funnel.

Theory 
Quicklime reacts with water to form calcium hydroxide. As in this reaction two substances – quicklime and water combine to form a new substance, therefore, this reaction is called combination reaction. This chemical change can be represented by the given chemical equation:
CBSE Class 10 Science Practical Skills – Types of Reactions 5
During this chemical change, heat is also released. Therefore, this is also an example of exothermic reaction.

Procedure And Observation Table
The experimental procedure is described in the table:
CBSE Class 10 Science Practical Skills – Types of Reactions 6

Result
Two compounds, viz. quicklime and water combine to form calcium hydroxide. Therefore, this reaction is an example of combination reaction.

Precautions 

  1. Quicklime can cause severe burns, therefore, it should be handled with spatula.
  2. As the reaction between quicklime and water is exothermic, water should be poured over quicklime slowly.
  3. The filtrate collected should be clear.

EXPERIMENT 3(b)

Aim 
To perform and observe the action of heat on crystals of ferrous sulphate and classify the reaction.

Material Required 
Ferrous sulphate crystals, test tubes, test tube holder, blue limus paper.

Theory
The crystals of ferrous sulphate are green in colour. When these crystals are heated, following reaction takes place.
CBSE Class 10 Science Practical Skills – Types of Reactions 8
In this reaction, a single reactant breaks down to give simple products. Therefore, this is a decomposition reaction.
Ferrous sulphate crystals (FeS04.7H20) lose water when heated and the colour of crystals changes. It then decomposes to ferric oxide(Fe203), sulphur dioxide (S02) and sulphur trioxide (S03). Ferric oxide is solid while S02 and S03 are gases. Both S02 and S03 are acidic and hence, these gases turn the blue litmus red. Sulphur dioxide can reduce an acidified solution of potassium dichromate. This reaction can be utilised to confirm the presence of sulphur dioxide.
CBSE Class 10 Science Practical Skills – Types of Reactions 9

Procedure And Observation Table 
The experimental procedure is given in the following table:CBSE Class 10 Science Practical Skills – Types of Reactions 10

Resulst
On heating, ferrous sulphate decomposes to give ferric oxide, sulphur dioxide and sulphur trioxide. This decomposition reaction.

Precautions  

  1. While heating ferrous sulphate, keep the mouth of test tube away from you and your classmates.

EXPERIMENT 3(c)

Aim
To perform and observe the reaction of iron nails kept in copper sulphate solution and classify the reaction.

Materials Required
Iron nails, copper sulphate solution, test tubes, test tube stand, sandpaper and thread.

Theory
When an iron nail is immersed in copper sulphate solution, following reaction takes place:
CBSE Class 10 Science Practical Skills – Types of Reactions 12
In the above reaction, iron ions (Fe2+) being more reactive displaces copper ions (Cu2+) and a new compound ferrous sulphate is formed. This type of reactions is called displacement reaction.

Procedure 

  1. Take two iron nails and clean them by rubbing with sandpaper.
  2. Take two test tubes and mark them as ‘A’ and ‘B’.
  3. In each test tube, pour about 10 ml of copper sulphate solution.
  4. Tie one iron nail with a thread and immerse this carefully in the copper sulphate solution in test tube A for about 20 minutes. Keep aside one nail for comparison.
  5. After 20 minutes, take out the iron nail from the copper sulphate solution.
  6. Compare the intensity of blue colour of copper sulphate solutions of both   the  test    tubes ‘A’ and ‘B\
  7. Also, compare the colour of iron nail dipped in copper sulphate solution with one kept aside.
    CBSE Class 10 Science Practical Skills – Types of Reactions 13

Observations
The initial colour of copper sulphate solution was blue which after immersing iron nails turns to light green.
The initial colour of iron nail was grey. After immersing the nail into copper sulphate solution, a brown coating developed over it. Because of this coating iron nail appears reddish brown.

Result
On keeping the iron nails in copper sulphate solution, a displacement reaction takes place. In this displacement reaction, iron displaces copper and two new products ferrous sulphate and copper are formed.

Precautions 

  1. The iron nails should be cleaned by rubbing them with a sandpaper.
  2. The test tube containing iron nails and copper sulphate solution should not be disturbed.

EXPERIMENT 3(d)

Aim
To perform and observe the reaction between sodium sulphate and barium chloride solutions and classify the reaction.

Materials Required
Sodium sulphate solution, barium chloride solution, test tubes, beaker.

Theory
When the solutions of sodium sulphate and barium chloride are mixed, a white precipitate of barium sulphate is formed. Chemical equation for this chemical change can be given as follows:
CBSE Class 10 Science Practical Skills – Types of Reactions 14
In this reaction, both sodium sulphate and barium chloride exchange ions. Hence, this type of reaction is called double displacement reaction.

Procedure 

  1. Take 5 ml of sodium sulphate solution in a test tube and mark it as ‘A’.
  2. Take 5 ml of barium chloride solution in another test tube and mark it as ‘B’.
  3. Mix the solutions of test tubes ‘A’ and ‘B’ in a beaker.
  4. With the help of a clean glass rod, stir the mixture kept in beaker.
  5. Record your observation.

CBSE Class 10 Science Practical Skills – Types of Reactions 15

Observation
On mixing the solutions of sodium sulphate and barium chloride, a white precipitate is formed.

Result
On mixing the solutions of sodium sulphate and barium chloride, a double displacement reaction takes place.
In this reaction sodium sulphate and barium chloride exchange ions and new products barium sulphate (white ppt) and sodium chloride are formed.

Precautions                                                                                                                                   –

  1. Test tubes, beaker and glass rod should be cleaned.
  2. Equal volumes of sodium sulphate and barium chloride solutions should be used.

INTERACTIVE SESSION

 

Question 1:
What is the aim of your experiment?
Answer:
The aim of my experiment is to study the various types of chemical reactions.

Question 2:
How many types of chemical reactions are there?
Answer:
There are basically four types of chemical reactions, Combination reaction, Decomposition reaction, Displacement reaction and Double displacement reaction.

Question 3:
What type of reaction is combustion of hydrogen?
Answer:
It is a combination reaction.

Question 4:
Give the equation involved in the above process.
Answer:
2H2(g) + O2(g)→ 2H2O(l)

Question 5:
Can the above reaction be classified as a redox reaction?
Answer:
Yes, it can be classified as a redox reaction.

Question 6:
If we add Ag to an aqueous solution of CuS04, what happens and why?
Answer:
No change is observed because Ag being less reactive than Cu is unable to displace it from its salt solution.

Question 7:
What would happen if dil. HCl is added to (CH3COO)2Pb (lead acetate)?
Answer:
A white precipitate of PbCl2 will be obtained.

Question 8:
Give the equation involved and identify the type of chemical reaction.
Answer:
The equation involved is
(CH3COO)2Pb(aq) + 2HCl(aq) → 2CH3COOH(aq) + PbCl2(s)
This is a double displacement reaction.

Question 9:
Identify the type of chemical reaction occurring in the forward and backward processes of
CaC03 \(\overset { \Delta  }{ \rightleftharpoons  }\)CaO + C02.
Answer:
The forward reaction is a decomposition reaction while the backward reaction is a combination reaction.

Question 10:
What type of reaction is
Na2C03(aq) + 2HCl(aq)→ 2NaCl(aq) + H20(l) + C02(g)?
Answer:
It is a double displacement reaction.

Question 11:
How is it a double displacement reaction?
Answer:
In this reaction, the \({ CO }_{ 3 }^{ 2- }\) ions and Cl– ions are interchanging their positions, and H2C03 which is formed undergoes decomposition to give H20 and C02 as
H2C03(aq) \(\rightleftharpoons\)H20(aq) + CO2(g)

Question 12:
Why do displacement reactions occur?
Answer:
Displacement reactions occur due to the difference in reactivities of the elements. A more reactive element (metal or non-metal) displaces a less reactive element (metal or non-metal) from its salt solution.

NCERT LAB MANUAL QUESTIONS

Question 1:
Fill in the blanks:
(а) Sodium sulphate and barium chloride are ___________ (ionic/covalent) compounds.
(b) As the white precipitate of barium sulphate is formed___________________ (immediately/some­time after mixing the two solutions), the reaction between____________________ (ionic/covalent)
compounds is   (instantaneous/slow).
Answer:
(a) ionic
(b) immediately, ionic, instantaneous.

Question 2:
Why does the colour of copper sulphate solution change when an iron nail is dipped in it?
Answer:
The colour of copper sulphate solution changes when an iron nail is dipped in it because Fe is more reactive than Cu and can displace it from its salt solution.
CBSE Class 10 Science Practical Skills – Types of Reactions 16

Practical Based Questions 

Multiple Choice Questions/VSA

1. A student took solid quicklime in a china dish and added a small amount of water. He heard [AI 2010]
(a) a popping sound
(b) a crackling sound
(c) a hissing sound
(d) no sound at all

2. On heating ferrous sulphate crystals, one would get  [CBSE 2012, CBSE Sample Paper 2009]
(a) sweet smell
(b) rotten egg smell
(c) irritating choking smell
(d) none of the above

3. Hydrated ferrous sulphate is commonly known as
(a) blue vitriol
(b) green vitriol
(c)  yellow vitriol
(d) brown  vitriol

4. On passing C02 gas through the product formed by the reaction between CaO and H20, solution becomes
(a)  red
(b) pink
(c)  black
(d) white

5. On heating ferrous sulphate in a test tube it undergoes
(а) combination reaction
(b) decomposition reaction
(c) displacement reaction
(d) double displacement reaction

6. An iron nail is placed in a solution of copper sulphate. The nail is taken out after 10 minutes. The nail will be found to be covered with [CBSE 2012]
(a) brown deposit
(b) black deposit
(c) white deposit
(d) yellow deposit

7. CaO is commonly known as
(a) lime water
(b) slaked lime
(c) quicklime
(d) lemon water

8. The solid residue obtained on heating ferrous sulphate in a glass tube is
(a) ferrous sulphide
(b) ferrous oxide
(c) ferric oxide
(d) ferrous sulphite

9. Which of the following information about the reaction of CaO with water is not true?
(a) CaO reacts with water vigorously.
(b) During the reaction the test tube becomes hot.
(c) CaO reacts with water to form slaked lime.
(d) During the reaction dazzling white is produced.

10. When iron nails are kept in the solution of copper sulphate, the colour of the solution changes from
(a) green to yellow
(b) blue to green
(c) green to blue
(d) yellow to green

11. Precipitate formed on mixing the solutions of barium chloride-and sodium sulphate is of
(a) barium sulphate
(b) sodium chloride
(c) barium sulphite
(d) sodium sulphite

12. In ferrous sulphate, the valency of iron is
(a) 1
(b) 2
(c) 3
(d) 4

13. Which of the following represents a combination reaction?
(a) Reaction of zinc metal with copper sulphate solution
(b) Heating of lead nitrate
(c) Reaction between silver nitrate and sodium chloride
(d) Burning of magnesium in air.

Short Answer Questions

1. What is the difference between burning of magnesium ribbon in air and heating of ferrous sulphate crystals? Write equations for these reactions.

2. Why does a moist blue litmus paper turn red when it is brought near the mouth of the test tube in which ferrous sulphate crystals are being heated?

3. What happens when:
(a) solutions of sodium sulphate and barium chloride are mixed?
(b) an iron nail is dipped in copper sulphate solution for 20 minutes?

4. What precautions would you take while handling quicklime?

5. What will be the nature of solution formed when calcium oxide is dissolved in water? Name the substance formed when carbon dioxide gas is passed through this solution.

ANSWER KEY

Multiple Choice Questions/VSA

  1. (c)
  2. (c)
  3. (b)
  4. (d)
  5. (b)
  6. (a)
  7. (c)
  8. (c)
  9. (d)
  10. (b)
  11. (a)
  12. (b)
  13. (d)

Short Answer Questions
1.
CBSE Class 10 Science Practical Skills – Types of Reactions 17

2. On heating ferrous sulphate crystals (FeS04.7H20) it decomposes to ferric oxide, sulphur dioxide and sulphur trioxide. Ferric oxide is solid while sulphur dioxide and sulphur trioxide are gases. Both sulphur dioxide and sulphur trioxide are acidic and hence these gases turn the moist blue litmus red.

3. (a) When solutions of sodium sulphate and barium chloride are mixed, a white precipitate of barium sulphate is formed.

CBSE Class 10 Science Practical Skills – Types of Reactions 18

(b) When an iron nail is dipped in copper sulphate solution, following reaction takes place
CBSE Class 10 Science Practical Skills – Types of Reactions 19
In the above reaction, iron ions (Fe2+) being more reactive displaces copper ions (Cu2+) and a new compound ferrous sulphate is formed.

4. (i) Quicklime can cause severe bums, therefore it should be handled with a spatula.
(ii) As reaction between quicklime and water is exothermic, water should be poured over quicklime slowly.

5. On dissolving calcium oxide in water, calcium hydroxide is formed. When a drop of this liquid is put on a red litmus paper, it turns blue. This shows calcium hydroxide is basic in nature. When carbon dioxide gas is passed through calcium hydroxide (lime water), it turns milky due to formation of calcium carbonate.
CBSE Class 10 Science Practical Skills – Types of Reactions 20

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CBSE Previous Year Solved Papers Class 12 Maths Delhi 2013

CBSE Previous Year Solved  Papers Class 12 Maths Delhi 2013

Time allowed: 3 hours                                                                                          Maximum Marks : 100
General Instructions:

  1. All questions are compulsory.
  2. Please check that this question paper contains 26 questions.
  3. Questions 1-6 in Section A are very short-answer type questions carrying 1 mark each.
  4. Questions 7-19 in Section B are long-answer I type questions carrying 4 marks each.
  5. Questions 20-26 in Section C are long-answer II type questions carrying 6 marks each.
  6. Please write down the serial number of the question before attempting it.

SET I

Note: Except for the following questions, All the remaining question s have been asked in previous set.

SECTION – A

cbse-previous-year-solved-papers-class-12-maths-delhi-2013-1
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-2
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-3
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-4
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-5
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-6

SECTION – B

cbse-previous-year-solved-papers-class-12-maths-delhi-2013-7
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-8
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-9
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-10
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-11
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-12
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-13
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-14
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-15
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-16
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-17
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-18
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-19
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-20
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-21
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-22
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-23
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-24
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-25

22. A speaks truth in 60% of the cases, while B in 90% of the cases. In what percent of cases are they likely to contradict each other in stating the same fact ? In the cases of contradiction do you think, the statement of B will carry more weight as he speaks truth in more number of cases then A ?
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-26

SECTION – C

23. A school wants to award its students for the values of Honesty, Regularity and Hard work with a total cash award of Rs 6,000. Three times the award money for Hard work added to that given for honesty amounts to Rs 11,000. The award money given for Honesty and Hard work together is double the one given for Regularity. Represent the above situation algebraically and find the . award money for each value, using matrix method. Apart from these values namely, Honesty, Regularity and Hard work, suggest one more value which the school must include for awards. [6]
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-27
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-28
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-29
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-30
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-31
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-32
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-33
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-34
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-35
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-36
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-37
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-38
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-39

28. A cooperative society of farmers has 50 hectares of land to grow two crops A and B. The profits from crops A and B per hectare are estimated as Rs 10,500 and Rs 9,000 respectively. To control weeds, a liquid herbicide has to be used for crops A and B at the rate of 20 litres and 10 litres per hectare, respectively. Further not more than 800 litres of herbicide should be used in order to protect fish and wildlife using a pond which collects drainage from this land. Keeping in mind that the protection of fish and other wildlife is more important than earning profit, how much land should be allocated to each crop so as to maximize the total profit ? Form an LPP from the above and solve it graphically. Do you agree with the message that the protection of wildlife is utmost necessary to preserve the balance in environment ? [6]
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-40
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-41
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-42

29. Assume that the chances of a patient having a heart attack is 40%. Assuming that a meditation and yoga course reduces the risk of heart attack by 30% and prescription of certain drug reduces its chance by 25%. At a time a patient can choose any one of the two options with equal possibilities. It is given that after going through one of the two options, the patient selected at random suffers a heart attack. Find the probability that the patient followed a course of meditation and yoga. Interpret the result and state which of the above stated methods is more beneficial for the patient. [6]
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-43

SET II

Note: Except for the following questions, All the remaining questions have been asked in previous Sets.

SECTION – A

cbse-previous-year-solved-papers-class-12-maths-delhi-2013-44

SECTION – B

16. P speaks truth in 70% of the cases and Q in 30% of the cases. In what per cent of cases are they likely to agree in stating the same fact ? Do you think, when they agree, means both are speaking truth?
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-45
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-46
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-47
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-48
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-49

SECTION – C

cbse-previous-year-solved-papers-class-12-maths-delhi-2013-50
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-51
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-52
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-53

SET III

Note: Except for the following questions, All the remaining questions have been asked in previous Sets.

SECTION – A

cbse-previous-year-solved-papers-class-12-maths-delhi-2013-54

SECTION – B

11. A speaks truth in 75% of the cases, while B in 90% of the cases. In what percent of cases are the likely to contradict each other in stating the same fact ? Do you think that statement of B is true ?
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-55
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-56
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-57
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-58

SECTION – C

25. Find the coordinates of the point where the line through (3, – 4, – 5) and (2, – 3,1) crosses the plane, passing through the points (2, 2, 1), (3, 0, 1) and (4,-1,0). [6]
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-59
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-60
cbse-previous-year-solved-papers-class-12-maths-delhi-2013-61

CBSE Previous Year Solved Papers Class 12 Physics Delhi 2015

CBSE Previous Year Solved  Papers  Class 12 Physics Delhi 2015

Time allowed : 3 hours                                                                                           Maximum Marks: 70

General Instructions:

    1.  All questions are compulsory. There are 26
      questions in all.
    2.  This question paper has five sections : Section A, Section B, Section C, Section D and Section E.
    3. Section A contains five questions of one mark each, Section B contains five questions of two marks each, Section C contains twelve questions of three marks each, Section D contains one value based question of four marks and Section E contains three questions of five marks each.
    4.  There is no overall choice. However, an internal choice has been provided in one question of two marks, one question of three marks and all the three questions of five marks weight age. You have to attempt only one of the choices in such questions.
    5. You may use the following values of physical constants wherever necessary:

cbse-previous-year-solved-papers-class-12-physics-outside-delhi-2016-1.

SET I

SECTION-A

Question.1.Define capacitor reactance. Write its S.I. units.
Answer : Capacitor reactance is the resistance offered by a capacitor to the flow of a.c. It is given by
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-1

Question.2. What is the electric flux through a cube of side 1 cm which encloses an electric dipole ?
Answer : The electric flux through a cube of side 1 cm which encloses an electric dipole will be zero, as net charge enclosed by a cube is zero.

Question.3. A concave lens of refractive index 1.5 is immersed in a medium of refractive index 1.65. What is the nature of the lens ?
Answer : Since μg lens < μsurroundings.
It behaves like a converging lens.

Question. 4. How are side bands produced ?
Answer : Side bands are produced during the process of modulation. During modulation the audio frequency modulating signal wave is superimposed on a high frequency wave called carrier wave. Any form of modulation produces , frequencies that are the sum and difference of the carrier and modulating frequencies. These frequencies are called as side bands.
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-2
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-3

Question.5. Graph showing the variation of current versus voltage for a material GaAs is shown in the figure, Identify the region of:
(i) negative resistance
(ii) where Ohms law is obeyed.
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-4
Answer : (i) DE is the region of negative resistance because the slope of curve in this part is negative.
(ii) BC is the region where Ohms law is obeyed because in this part, the current varies linearly with the voltage.

SECTION – B

Question.6. A proton and an α -particle have the same deBroglie wavelength. Determine the ratio of (i) their accelerating potentials (ii) their speeds.
Answer : (i) The deBroglie wavelength of a particle is given by
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-5
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-6

Question.7. Show that the radius of the orbit in hydrogen atom varies as n2. Where n is the principal quantum number of the atom.
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-7
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-8

Question.8. Distinguish between ‘intrinsic’ semiconductors.
Answer :
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-9

Question.9. Use the mirror equation to show that an object placed between f and 2 f of a concave mirror produces a real image beyond 2f.
OR
Find an expression for intensity of transmitted light when a Polaroid sheet is rotated between two crossed Polaroids. In which position of the Polaroid sheet will the transmitted intensity be maximum ?
Answer :
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-10
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-11
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-12

Question.10. Use Kirchhoff’s rules to obtain conditions for the balance condition in a Wheatstone bridge.
Answer : Let us consider a Wheatstone bridge arrangement as shown below:
Wheatstone bridge is a special bridge type circuit which consists of four resistances, a galvanometer and a battery. It is used to determine unknown resistance.
In figure four resistance P, Q, R and S are connected in the form of four arms of a quadrilateral. Let the current given by battery in the balanced position be I. This current on reaching point A is divided into two parts I1 and I2. As there is no current in galvanometer in balanced state, therefore, current in resistances P and Q is Ii and in resistances R and S it is I2.
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-13

SECTION-C

Question.11. Name the parts of the electromagnetic spectrum which is
(a) suitable for radar systems used in aircraft navigation
(b) used to treat muscular strain
(c) used as a diagnostic tool in medicine
Write in brief, how these waves can be produced.
Answer : (a) Microwaves are suitable for radar systems that are used in aircraft navigation.
These rays are produced by special vacuum tubes, namely -klystrons, magnetrons and Gunn diodes.
(b) Infrared waves are used to treat muscular strain.
These rays are produced by hot bodies and molecules.
(c) X-rays are used as a diagnostic tool in medicine.
These rays are produced when high energy electrons are stopped suddenly on a metal of high atomic number.

Question.12. (i) A giant refracting telescope has an objective lens of focal length 15 m. If an eye-piece of focal length 1.0 cm is used. What is the angular magnification of the telescope ? (ii) If this telescope is used to view the moon. What is the diameter of the image of the moon formed by the objective lens ? The diameter of the moon is 3.48 x 108 m and the radius of lunar orbit is 3.8 x 108 cm.
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-14
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-15

Question.13. Write Einstein’s photoelectric equation and mention which important features in photoelectric effect can be explained with the help of this equation.
The maximum kinetic energy of the photo electrons gets doubled when the wavelength of light incident on the surface changes from λ1 to λ2. Derive the expressions for the threshold wavelength λ0 and work function for the metal surface.
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-16
The above equations explains the following results.
(1) If v < v0, then the maximum kinetic energy is negative, which is impossible. Hence, photoelectric emission does not take place for the incident radiation below the threshold frequency. Thus, the photoelectric emission can take place if v>v0.
(2) The maximum kinetic energy of emitted photoelectrons is directly proportional to the frequency of the incident radiation. This means that maximum kinetic energy of photo electron depends only on the frequency of incident light.
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-17

Question.14. In the study of Geiger-Marsdon experiment on scattering of a-particles by a thin foil of gold, draw the trajectory of a-particles in the Coulomb field of target nucleus. Explain briefly how one gets the information on the size of the nucleus from this study.
From the relation R = R0 A1/3, where R0 is constant and A is the mass number of the nucleus, show that nuclear matter density is independent of A.
OR
Distinguish between nuclear fission and fusion. Show how in both these processes energy is released. Calculate the energy release in MeV in the deuterium-tritium fusion reaction :
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-18
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-19
From this experiment, the following is observed :
(1) Most of the alpha particles pass straight through the gold foil. It means that they do not suffer any collision with golf atoms.
(2) About one alpha particle in every 8000 alpha particles deflects by more than 90°.
As most of the alpha particles go undeflected and only a few get deflected, this shows that most of the space in an atom is empty and at the centre of the atom, there exists a nucleus. By the number of the alpha particles deflected, the information regarding size of the nucleus can be known.
If m is the average mass of a nucleon and R is the nuclear radius, then mass of nucleus = mA, where A is the mass number of the element.
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-20
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-21

Question.15. Draw a block diagram of a detector for AM signal and show, using necessary processes and the wave forms, how the original message signal is detected from the input AM wave.
Answer :
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-22
When a message is received, it gets attenuated through the channel therefore, receiving antenna is to be followed by an amplifier and a detector. The camera frequency is usually changed to a lower frequency in an Intermediate Frequency (IF) stage. The detected signal may not be strong enough to be made use of and hence is required to be amplified.
In order to obtain the original message signal m(t) of angular frequency a simple method is used which is shown below in the form of a block diagram.
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-23
When the received modulated signal is passed through a rectifier, an envelope signal is produced. This envelope signal is the message signal. In order to retrieve the message, the signal is passed through an envelope detector.

Question.16. A cell of emf ‘E’ and internal resistance ‘r’ is connected across a variable load resistor R. Draw the plots of the terminal voltage V versus (i) R and (ii) the current i. It is found that when R = 4Ω, the current is 1A when R is increased to 9Ω, the current reduces to 0.5 A. Find the values of the emf E and internal resistance r.
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-24
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-25

Question.17. Two capacitors of unknown capacitance C1 and C2 are connected first in series and then in parallel across a battery of 100 V. If the energy stored in the two combinations is 0.045 J and 0.25 J respectively, determine the value of C1 and C2. Also calculate the charge on each capacitor in parallel combination.
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-26
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-27

Question.18. State the principle of working of a galvanometer. A galvanometer of resistance G is converted into a voltmeter to measure up to V volts by connecting a resistance R1 in series with the coil. If a resistance R2 is connected in series with it, then it can measure up to V/2 volts. Find the resistance, in terms of R1 and R2, required to be connected to convert it into a voltmeter that can read up to 2 V. Also find the resistance G of the galvanometer in terms of R1 and R2.
Answer : Principle : When a current-carrying coil is placed in a magnetic field, it experiences a torque. From the measurement of the deflection of the coil, the strength of the current can be computed. A high resistance is connected in series with the galvanometer to convert it into voltmeter. The value of the resistance is given by
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-28

Question.19. With what considerations in view, a photo diode is fabricated ? State its working with the help of a suitable diagram.Even though the current in the forward bias is known to be more than in the reverse bias, yet the photo diode works in reverse bias. What is the reason ?
Answer: A photo diode is used to observe the change in current with change in the light intensity under reverse bias condition.
In fabrication of photo diode, material chosen should have band gap —1.5 eV or lower so that solar conversion efficiency is better. This is the reason to choose Si or GaAs material.
Working : It is a p-n junction fabricated with a transparent window to allow light photons to fall on it. These photons generate electron hole pairs upon absorption. If the junction is reverse biased using an electrical circuit, these electron hole pair move in opposite directions so as to produce current in the circuit. This current is very small and is detected by the micro ammeter placed in the circuit.
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-29
A photo diode is preferably operated in reverse bias condition. Consider an n- type semiconductor. Its majority carrier (electron) density is much larger than the minority hole density i.e. n < < p. When illuminated with light, both types of carriers increase equally in number
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-30
That is, the fractional increase in majority carries is much less than the fractional increase in minority carriers. Consequently, the fractional change due to the photo-effects on the minority carrier dominated reverse bias current is more easily measurable than the fractional change in the majority carrier dominated forward bias current. Hence, photo diodes are preferable used in the reverse bias condition for measuring light intensity.

Question.20. Draw a circuit diagram of a transistor amplifier in CE configuration.Define the terms :
(i) Input resistance and (ii) Current amplification factor. How are these determined using typical input and output characteristics ?
Answer:
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cbse-previous-year-solved-papers-class-12-physics-delhi-2015-32

Question.21. Answer the following questions :
(a) In a double slit experiment using light of wavelength 600 nm, the angular width of the fringe formed on a distant screen is 0.1°. Find the spacing between the two slits. Light of wavelength 5000 A propagating in air gets partly reflected from the surface of water. How will the wavelengths and frequencies of the reflected and refracted light be affected ?
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Question.22. An inductor L of inductance XL is connected in series with a bulb B and an ac source. How would brightness of the bulb change when (i) number of turn in the inductor is reduced, (ii) an iron rod is inserted in the inductor and (iii) a capacitor of reactance XC= XL is inserted in series in the circuit. Justify your answer in each case.
Answer:
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-35
(i) When the number of turns in the inductor is reduced, its reactance XL decreases. The current in the circuit increases and hence brightness of the bulb increases.
(ii) When an iron rod is inserted in the inductor, the self inductance increases. Consequently, the inductive reactance XL = ωL increases. This decreases the current in the circuit and the bulb glows dimmer.
(iii) With capacitor of reactance XC=XL, the impedance
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-36
becomes minimum, the current in circuit becomes maximum. Hence the bulb glows with maximum brightness.

SECTION – D

Question.23. A group of students while coming from the school noticed a box marked “Danger H.T. 2200 V” at a substation in the main street. They did not understand the utility of a such a high voltage, while they argued the supply was only 220 V. They asked their teacher this question the next day. The . teacher thought it to be an important question and therefore, explained to the whole class.
Answer the following questions :
(i) What device is used to bring the high voltage down to low voltage of a.c. current and what is the principle of its working ?
(ii) Is it possible to use this device for bringing down the high dc voltage to the low voltage ? Explain.
(iii) Write the values displayed by the students and the teacher.
Answer : (i) The device that is used to bring high voltage down to low voltage of an a.c. current is a transformer. It works on the principle of mutual induction of two windings or circuits. When current in one circuit changes, emf is induced in the neighbouring circuit.
(ii) The transformer cannot convert d.c. voltages because it works on the principle of mutual induction. When the current linked with the primary coil changes the magnetic flux linked with the secondary coil also changes. This change in flux induces emf in the secondary coil. If we apply a direct current to the primary coil the current will remain constant. Thus, there is no mutual induction and hence no emf is induced.
(iii) The value of gaining knowledge and curiosity about learning new things is being displayed by the students. The value of providing good education and undertaking the doubts of students has been displayed by the teacher.

SECTION-E

Question.24. (a) State Ampere’s Circuital law. Use this law to obtain the expression for the magnetic field inside an air cored toroid of average radius, having ‘n’ turns per unit length and carrying a steady current I.
(b) An observer to the left of a solenoid of N turns each of cross section area A observes that a steady current I in it flows in the clockwise direction. Depict the magnetic field lines due to the solenoid specifying its polarity and show that it acts as a bar magnet of magnetic momentum M = NIA.
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-37
OR
(a) Define mutual inductance and write its S.I. units.
(b) Derive an expression for the mutual inductance of two long co-axial solenoids of same length wound one over the other.
(c) In an experiment two coils c1 and c2 are placed close to each other. Find out the expression for the emf induced in the coil c1 due to a change in the current through the coil c2.
Answer : (a) Amperes circuital law in electro magnetism is analogous to Gauss law in electrostatics. This law states that “The line integral of resultant magnetic field along a closed plane curve is equal to µtime the total current crossing the area bounded by the closed curve provided the electric field
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-38
Given :
r = Average radius of the toroid
I = Current through the solenoid .
n = Number of turns per unit length
To determine the magnetic field inside the toroid, we consider three amperian loops (loop 1, loop 2 and loop 3) as show in the figure below.
cbse-previous-year-solved-papers-class-12-physics-delhi-2015-39
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This is the expression for magnetic field inside air-cored toroid.
(b) Given that the current flows in the clockwise direction for an observer on the left side of the solenoid. This means that left face of the solenoid acts as south pole and right face acts as north pole. Inside a bar magnet the magnetic field lines are directed from south to north. Therefore, the magnetic field lines are directed from left to right in the solenoid.
Magnetic moment of single current carrying loop is given by
m = LA
where
I = Current flowing through the loop A = Area of the loop
So, Magnetic moment of the whole solenoid is given by
M = Nw’ = N(IA)
OR
(a) Mutual inductance is the property of two coils by the virtue of which each opposes any change in the value of current flowing through the other by developing an induced emf. The SI unit of mutual inductance is henry and its symbol is H.
(b) Consider two long solenoids S1 and S2 of same length l such that solenoid S2 surrounds solenoid S1 completely.
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Question.25. (a) A point object ‘O’ is kept in a medium of refractive index n in front of a convex spherical surface of radius of curvature R which separate the second medium of refractive index n% from the first one as shown in the figure.
Draw the ray diagram showing the image formation and deduce the relationship between the object distance and the image distance in terms of n, n1 and R.
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(b) When the image formed above acts as a virtual object for a concave spherical surface separating the medium n2 from n1 (n2 > n1) draw this ray diagram and write the similar (similar to (a)) relation. Hence obtain the expression for the Lens Makers formula.
Answer : (a) Let a spherical surface separate a rarer medium of refractive index n1 from second medium of refractive index n2. Let C be the centre of curvature and R = MC be the radius of the surface.
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Consider a point object O lying on the principle axis of the surface. Let a ray starting from O incident normally on the surface along OM and pass straight. Let another ray of light incident on NM along ON and refract along NI.
From M, draw MN perpendicular to OI. ”
The above figure shows the geometry of formation of image I of an object O and the principal axis of a spherical surface with centre of curvature C. and radius of curvature R.
Let us make the following assumptions :
(i) The aperture of the surface is small as compared to the other distance involved.
(ii) Nil will be taken as nearly equal to the length of the perpendicular from the point N on the principal axis.
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Question.26.
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OR
(a) Explain, using suitable diagrams, the difference in the behaviour of a (i) conductor and (ii) dielectric in the presence of external electric field. Define the terms polarization of a dielectric and write its relation with susceptibility.
(b) A thin metallic spherical shell of radius carries a charge Q on its surface. A point charge Q/2 is placed at its centre C and another charge +2Q is placed outside the shell at a distance x from the centre as shown in the figure. Find (i) the force on the charge at the centre of shell and at the point A, (ii) the electric flux through the shell.
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When external electric field is applied, dipoles are created (in case of non-polar dielectrics). The placement of dipoles is as shown in the given figure. An internal electric field is created which reduces the external electric field.
Polarization of dielectric (P) is defined as the dipole moment per unit volume of the polarized dielectric.
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Report Writing On Road Accident For Class 10 Format, Examples, Topics, Exercises

Report Writing On Road Accident For Class 10 Format, Examples, Topics, Exercises

Report Writing On Road Accident For Class 10 Format, Examples, Topics, Exercises

Introduction:

A road accident is a sudden, unexpected, and unfortunate incident that can lead to severe damage to property, injuries, or even death. It can happen to anyone, at any time, and anywhere. In this report, we will discuss the format, examples, topics, and exercises related to writing a report on road accidents for Class 10.

Format Of Report Writing On Road Accident For Class 10:

A report on a road accident should have a standard format, which includes the following elements:

1. Title: The title should be concise and descriptive, indicating the main focus of the report.
2. Introduction: The introduction should provide a brief overview of the accident, including the location, time, and date of the incident.
3. Background: The background should provide some context for the accident, such as the weather conditions, road conditions, and any other factors that may have contributed to the accident.
4. Description of the Accident: This section should provide a detailed description of the accident, including the vehicles involved, the number of casualties, and the severity of the injuries.
5. Analysis: The analysis should include an examination of the causes of the accident and any contributing factors, such as driver error, mechanical failure, or poor road design.
6. Conclusions: The conclusions should summarize the findings of the report, including any recommendations for improving road safety and preventing similar accidents in the future.
7. References: The references should include any sources used in the report, such as newspaper articles or police reports.

Also Read: Report Writing for Class 11

Examples Of Report Writing On Road Accident For Class 10:

Example 1: A Report on a Road Accident

Title: Car Accident on the Highway

Introduction: On the morning of June 15th, a car accident occurred on the highway near the city of XYZ. The accident resulted in two fatalities and several injuries.

Background: The weather was clear and dry at the time of the accident, and the road was in good condition. However, there was heavy traffic on the highway due to a construction project in the area.

Description of the Accident: The accident involved two vehicles, a sedan, and an SUV. The sedan was traveling northbound on the highway when it collided with the SUV, which was traveling southbound. The collision caused both vehicles to spin out of control and crash into the median barrier.

Analysis: The cause of the accident was determined to be driver error. The driver of the sedan was distracted by their cell phone and failed to see the SUV approaching in the opposite lane. Additionally, the heavy traffic on the highway may have contributed to the accident by limiting the visibility of the drivers.

Conclusions: To prevent similar accidents in the future, it is recommended that drivers avoid distractions while driving, especially on busy highways. Additionally, highway construction projects should be carefully planned to minimize the impact on traffic flow and visibility.

Example 2: A Report on a Road Accident

Title: Truck Collision on Rural Road

Introduction: On the evening of September 20th, a truck collision occurred on a rural road outside the town of ABC. The accident resulted in significant property damage but no injuries.

Background: The weather was cloudy and rainy at the time of the accident, and the road was wet and slippery. The road was also narrow and had many sharp turns.

Description of the Accident: The accident involved two trucks, a delivery truck and a dump truck. The delivery truck was traveling downhill when it collided with the dump truck, which was traveling uphill. The collision caused the delivery truck to spin out of control and crash into a nearby field.

Analysis: The cause of the accident was determined to be a combination of factors, including poor road conditions, driver error, and poor visibility due to the weather. The driver of the delivery truck was driving too fast for the conditions and failed to navigate the sharp turn in the road.

Conclusions: To prevent similar accidents in the future, it is recommended that drivers slow down and drive cautiously on narrow, winding roads, especially in adverse weather conditions. It is also important for truck drivers to be properly trained and for trucks to be regularly maintained to ensure that they are safe to operate on the road.

Examples Of Report Writing On Road Accident For Class 10

Topics For Report Writing On Road Accident For Class 10:

There are several topics that can be explored when writing a report on road accidents for Class 10. Some of these topics include:

1. The causes of road accidents
2. The impact of road accidents on society
3. Measures for improving road safety
4. The role of law enforcement in preventing road accidents
5. The importance of driver education and training
6. The impact of technology on road safety
7. Case studies of recent road accidents and their causes
8. The cost of road accidents to society

Exercises For Report Writing On Road Accident For Class 10:

To practice writing a report on a road accident, Class 10 students can try the following exercises:

Exercise 1: Write a report on a recent road accident that occurred in your local area. Include a description of the accident, an analysis of the causes, and recommendations for improving road safety.

Exercise 2: Choose a topic related to road accidents, such as the impact of technology on road safety or the importance of driver education and training. Conduct research on the topic and write a report summarizing your findings.

Exercise 3: Analyze a recent news article about a road accident and write a report on the causes of the accident and the steps that could be taken to prevent similar accidents in the future.

Conclusion On Report Writing On Road Accident For Class 10:

Writing a report on road accidents for Class 10 can be a valuable exercise in developing research, analysis, and writing skills. By following a standard format, exploring a range of topics, and practicing with exercises, students can gain a deeper understanding of the causes of road accidents and the measures that can be taken to prevent them.

CBSE Previous Year Solved Papers Class 12 Physics Delhi 2013

CBSE Previous Year Solved  Papers  Class 12 Physics Delhi 2013

Time allowed : 3 hours                                                                                           Maximum Marks: 70

General Instructions:

    1.  All questions are compulsory. There are 26 questions in all.
    2.  This question paper has five sections : Section A, Section B, Section C, Section D and Section E.
    3. Section A contains five questions of one mark each, Section B contains five questions of two marks each, Section C contains twelve questions of three marks each, Section D contains one value based question of four marks and Section E contains three questions of five marks each.
    4.  There is no overall choice. However, an internal choice has been provided in one question of two marks, one question of three marks and all the three questions of five marks weight age. You have to attempt only one of the choices in such questions.
    5. You may use the following values of physical constants wherever necessary:

cbse-previous-year-solved-papers-class-12-physics-outside-delhi-2016-1.

SET I

Note : Except for the following questions all the remaining question have been asked in Previous Set.

Question.1. What are permanent magnets? Give one example.
Answer : The magnets which have high retentivity and high coercivity are known as permanent magnets. For example : Steel

Question.2. What is the geometrical shape of equipotential surface due to a single isolated charge?
Answer : The equipotential surfaces of an isolated charge are concentric spherical shells and the distance between the shells increase with the decrease in electric field and vice-versa.
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-1

Question.3. Which of the following waves can be polarized (i) Heat waves (ii) Sound waves? Give reason to support your answer.
Answer : Heat waves can be polarized as they are transverse waves whereas sound waves cannot be polarized as they are longitudinal waves.
Transverse waves can oscillate in the direction perpendicular to the direction of its transmission but longitudinal waves oscillate only along the direction of its transmission. So, longitudinal waves cannot be polarized.

Question.4. A capacitor has been charged by a dc source. What are the magnitude of conduction and displacement current, when it is fully charged?
Answer : Electric flux through plates of capacitor,
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As voltage becomes constant when capacitor is fully charged.

Question.5. Write the relationship between angle of incidence ‘i’, angle of prism ‘A’ and angle of minimum deviations ∆m for a triangular prism.
Answer : The relation between the angle of incidence i, angle of prism A, and the angle of minimum deviation ∆m, for a triangular prism is given by i= (A+∆m)/2

Question.6. The given graph shows the variation of photo-electric current (I) versus applied voltage (V) for two different photosensitive materials and for two different intensities of the incident radiations. Identify the pairs of curves that correspond to different materials but same intensity of incident radiation.
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Answer : Curves 1 and 2 correspond to similar materials while curves 3 and 4 represent different materials, since the value of stopping potential for 1, 2 and 3, 4 are the same. For the given frequency of the incident radiation, the stopping potential is independent of its intensity.
So, the pairs of curves (1 and 3) and (2 and 4) correspond to different materials but same intensity of incident radiation.

Question.7. A 10 V battery of negligible internal resistance is connected across a 200 V battery and a resistance of 38Ω as shown in the figure. Find the value of the current in circuit.
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Answer : Since, the positive terminal of the batteries are connected together, so the equivalent emf of the batteries is given by
E = 200-10= 190 V
Hence, the current in the circuit is given by
I=E/R=190/38=5A

Question.8. The emf of a cell is always greater than its terminal voltage. Why? Give reason.
Answer : The emf of a cell is greater than its terminal voltage because there is some potential drop across the cell due to its small internal resistance.

Question.9. (a) Write the necessary conditions for the phenomenon of total internal reflection to occur.
(b) Write the relation between the refractive index and critical angle for a given pair of optical media.
Answer : (a) Necessary conditions for total internal reflection to occur are :
(i) The incident ray on the interface should travel in optically denser medium.
(ii) The angle of incidence should be greater than the critical angle for the given pair of optical media.
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Where a and b are the rarer and denser media respectively. C is the critical angle for the given pair of optical media.

Question.10. State Lenzs law.
A metallic rod held horizontally along east-west direction, is allowed to fall under gravity. Will there be an emf induced at its ends? Justify your answer.
Answer : Lenz’s law states that the polarity of induced emf is such that it produces a current which opposes the change in magnetic flux that produces it.
Emf will be induced in the rod as there is change in magnetic flux.
When a metallic rod held horizontally along east-west direction, is allowed to fall freely under gravity i.e. fall from north to south, the magnetic flux changes and the emf is induced in it.

Question.11. A convex lens of focal length 25 m is placed co axially in contact with a concave lens of focal length 20 cm. Determine the power of the combination. Will the system be converging or diverging in nature?
Answer : We have focal length of convex lens,
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The focal length of the combination = -1m = -100cm As the focal length is negative, the system will be diverging in nature.

Question.12. An ammeter of resistance 0.80 Ω can measure current up to 1.0 A.
(i) What must be the value of shunt resistance to enable the ammeter to measure current up to 5.0 A?
(ii) What is the combined resistance of the ammeter and the shunt?
Answer : We have, resistance of ammeter, RA = 0.80 ohm
Maximum current across ammeter, IA = 1.0 A.
So, voltage across ammeter, V= IR= 1 x 0.80 = 0.8 V
Let the value of shunt be x.
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-7

Question.13. In the given circuit diagram a voltmeter ‘V is connected across a lamp ‘L’. How would (i) the brightness of the lamp and (ii) voltmeter reading ‘V’ be affected, if the value of resistance ‘R’ is decreased? Justify your answer.
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Answer : The given figure is Common Emitter (CE) configuration of an n-p-n transistor is shown in the figure. The input circuit is forward biased and collector circuit is reverse biased.
If resistance R decreases, forward biased in the input circuit will increase, thus the base current (Ib) will decrease and the emitter current (IE) will increase. This will increase the collector current (IC) as IE = IB + IC.
When IC increases which flows through the lamp, the voltage across the bulb will also increase making the lamp brighter and the voltmeter is-connected in parallel with the lamp, the reading in the voltmeter will also increase.

Question.14. (a) An EM wave is, travelling in a medium with a velocity \(v = v\hat { i } \)Draw a sketch showing the propagation of the EM wave, indicating the direction of the oscillating electric and magnetic fields.
(b) How are the magnitudes of the electric and magnetic fields related to velocity of the EM wave?
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-9

Question.15. Block diagram of a receiver is shown in the figure :
(a) Identify ‘X’ and ‘Y’
(b) Write their functions.
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-10
Answer : From the given block diagram of demodulator of a typical receiver, we can conclude the following things :
(a) X represents Intermediate Frequency (IF) stage while Y , represents an amplifier.
(b) At IF stage, the carrier frequency is transformed to a lower frequency then in this process, the modulated signal is detected. The function of amplifier is to amplify the detected signal which may not be strong enough to be made use of and hence is essential.

Question.16. Explain, with the help of a circuit diagram, the working of a photo diode. Write briefly how it is used to detect the optical signals.
OR
Mention the important consideration required while fabricating a p-n junction diode to be used as a Light Emitting Diode (LED). What should be the order of band gap of an LED if it is required to emit light in the visible range?
Answer : A junction diode made from light sensitive semi-conductor is called a photo diode.
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-11
An electrical device that is used to detect and convert light into an energy signal with the use of a photo detector is known as a photo diode. The light that falls on it controls the function of pn-junction. Suppose, the wavelength is such that the energy of a photon hc/λ is enough to break a valance
bond. There is an increase in number of charge carriers and hence the conductivity of the junction also increases. New hole-electron pairs are created when such light falls on the junction. If the junction is connected in a circuit, the intensity of the incident light controls the current in the circuit.
OR
1. The reverse breakdown voltage of LEDs are very low, which is around 5V. So enough care is to be taken while fabricating
a pn-junction diode such that the high reverse voltages do not occur across them.
2. There exist very small resistance to limit the current in LED. So, a resistor must be placed in series with the LED such that no damage is occurred to the LED.
The semiconductor used for fabrication of visible LEDs must at least have a band gap of 1.8 eV.

Question.17. Write three important factors which justify the need of modulating a message signal. Show diagrammatically how an amplitude modulated wave is obtained when a modulating signal is superimposed on a carrier wave.
Answer : Three important factors which justify the need of modulating a message signal:
(i) Size of antenna or aerial: For communication within the effective length of the antennas, the transmitting frequencies should be high, so modulation is required.
(ii) Effective power which is radiated by antenna : Since the power radiated from a linear antenna is inversely proportional to the square of the transmitting wavelength. As high powers are needed for good transmission, so higher frequency is required which can be achieved by modulation.
(iii) The interference of signals from different transmitters : To avoid the interference of the signals there is a need of high I frequency which can be achieved by the modulation.
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-12

Question.18. A capacitor of unknown capacitance is connected across a battery of Y volts. The charge stored in it is 360 μC. When potential across the capacitor is reduced by 120 V, the charge stored in it becomes 120 μC.
Calculate :
(i) The potential V and the unknown capacitance C.
(ii) What will be the charge stored in the capacitor, if the
voltage applied had increased by 120 V?
OR
A hollow cylindrical box of length 1 m and area of cross section 25 cm2 is placed in a three-dimensional coordinate system as shown in the figure. The electric field in the region is given by over right arrow [/latex]{ E } =50x\hat { i } [/latex], where E is NC-1 and x is in metres. Find
(i) Net flux through the cylinder.
(ii) Charge enclosed by the cylinder.
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-13
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-14
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-15

Question.19. (a) In a typical nuclear reaction, e.g.
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-16
although number of nucleons is conserved, yet energy is released. How? Explain.
(b) Show that nuclear density in a given nucleus is independent of mass number A.
Answer :
(a) In a nuclear reaction, the aggregate of the masses of the target nucleus (\(_{ 1 }^{ 2 }{ H }\)) and the bombarding particle may be greater or less than the aggregate of the masses of the product nucleus (\(_{ 3 }^{ 2 }{ He}\)) and the outgoing particle (\(_{ 0 }^{ 1 }{ n }\)) So from the law of conservation of mass-energy some energy (3.27 MeV) is evolved or involved in a nuclear reaction. This energy is called Q-value of the nuclear reaction.
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-17
Which shows that the density is independent of mass number A.

Question.20. (a) Why photoelectric effect cannot be explained on the basis of wave nature of light? Give reasons.
(b) Write the basic features of photon picture of electro-magnetic radiation on which Einstein’s photoelectric equation is based.
Answer : (a) Wave nature of radiation cannot explain the photoelectric effect because of:
(i) The immediate ejection of photo electrons.
(ii) The presence of threshold frequency for a metal surface.
(iii) The fact -that kinetic energy of the emitted electrons is independent of the intensity of light and depends upon its frequency.
Thus, the photoelectric effect cannot be explained on the basis of wave nature of light.
(b) Photon picture of electromagnetic radiation on which Einstein’s photoelectric equation is based on particle nature of light. Its basic features are :
(i) In interaction with matter, radiation behaves as if it is made up of particles called photons.
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-18
(iv) By increasing the intensity of light of given wavelength, there is only an increase in the number of photons per second crossing a given area, with each photon having the same energy. Thus, photon energy is independent of intensity of radiation.
(v) Photons are electrically neutral and are not deflected by electric and magnetic fields.
(vi) In a photon—particle collision (such as photon-electron collision), the total energy and total momentum are conserved. However, number of photons may not be observed.

Question.21. A metallic rod of length T is rotated with a frequency v with one end hinged at the centre and the other end at the circumference of a circular metallic ring of radius r, about an axis passing through the centre and perpendicular to the plane of the ring. A constant uniform magnetic field B parallel to the axis is present everywhere. Using Lorentz force, explain how emf is induced between the centre and the metallic ring and hence obtained the expression for it.
Answer : Suppose the length of the rod is greater than the radius of the circle and rod rotates anticlockwise and suppose the direction of electrons in the rod at any instant be along +y direction.
Suppose the direction of the magnetic field is along +z direction.
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Thus, the direction of force on the electrons is along – x axis. So, the electrons will move towards the centre i.e., the fixed end of the rod. This movement of electrons will effect in current and thus it will generate an emf in the rod between the fixed end and the point touching the ring.
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-20

Question.22. Output characteristics of an n-p-n transistor in CE configuration is shown in the figure. Determine :
(i) dynamic output resistance
(ii) dc current gain and
(iii) at current gain at an operating point VCE = 10 V, when IB = 30 μA.
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Question.23. Using Bohr’s postulates, obtain the expression for the total energy of the electron in the stationary states of the hydrogen atom. Hence draw the energy level diagram showing how the line spectra corresponding to Balmer series occur due to transition between energy levels.
Answer: According to Bohr’s postulates, in a hydrogen atom, a single electron revolves around a nucleus of charge +e. For an electron moving with a uniform speed in a circular orbit of a given radius, the centripetal force is provided by Coulomb force of attraction between the electron and the nucleus. The gravitational attraction may be neglected as the mass of electron and proton is very small. So,
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When the electron in a hydrogen atom jumps from higher energy level to the lower energy level, the difference of energies of the two energy levels is emitted as a radiation of particular wavelength. It is called a spectral line.
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-25

Question.24. (a) In what way is diffraction from each slit related to the interference pattern in a double slit experiment.
(b) Two wavelengths of sodium light 590 nm and 596 nm are used, in turn to study the diffraction taking place at a single slit of aperture 2 x 10-4 m. The distance between the slit and the screen is 1.5 m. Calculate the separation between the positions of the first maxima of the diffraction pattern obtained in the two cases.
Answer : (a) If the width of each slit is comparable to the wavelength of light used, the interference pattern thus obtained in the double-slit experiment is modified by diffraction from each of the two slits.
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-26

Question.25. In a series LCR circuit connected to an ac source of variable frequency and voltage v = vm sin ωt, draw a plot showing the variation of current (I) with angular frequency (ω) for two different values of resistance R1 and R2 (R1 > R2). Write the condition under which the phenomenon of resonance occurs. For which value of the resistance out of the two curves, a sharper resonance is produced? Define Q-factor of the circuit and give its significance.
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We can observe that the current amplitude is maximum at the resonant frequency ω0. Since im = Vm/R at resonance, the current amplitude for case R2 is sharper to that for case R1.
Quality factor or simply the Q-factor of a resonant LCR circuit is defined as the ratio of voltage drop across the capacitor (or inductor) to that of applied voltage.
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The Q factor determines the sharpness of the resonance curve and if the resonance is less sharp, the maximum current decreases and also the circuit is close to the resonance for a larger range Aoo of frequencies and the regulation of the circuit will not be good. So, less sharp the resonance, less is the selectivity of the circuit while higher is the Q, sharper is the resonance curve and lesser will be the loss in energy of the circuit.
When XL = XC or VL = VC, the LCR circuit is said to be in resonance condition.

Question.26. While travelling back to his residence in the car, Dr. Pathak was caught up in a thunderstorm. It became very dark. He stopped driving the car and waited for thunderstorm to stop. Suddenly he noticed a child walking alone on the road. He asked the boy to come inside the car till the thunderstorm stopped. Dr. Pathak dropped the boy at his residence. The boy insisted that Dr. Pathak should meet his parents. The parents expressed their gratitude to Dr. Pathak for his concern for safety of the child.
Answer the following questions based on the above information :
(a) Why is it safer to sit inside a car during a thunderstorm?
(b) Which two values are displayed by Dr. Pathak in his action?
(c) Which values are reflected in parents’ response to Dr. Pathak?
(d) Give an example of similar action on your part in the part from everyday life.
Answer: (a) It is safer to be inside a car during thunderstorm because the car acts like a Faraday cage.
(b) Awareness and humanity
(c) Gratitude and obliged
(d) Once I came across to a situation where a puppy was struck in the middle of a busy road during rain and was not able to cross due to heavy flow, so I quickly rushed and helped him.

Question.27. (a) Draw a ray diagram showing the image formation by a compound microscope. Hence obtain expression for total magnification when the image is formed at infinity.
(b) Distinguish between myopia and hypermetropia. Show diagrammatically how these defects can be corrected.
OR
(a) State Huygens principle. Using this principle draw a diagram to show how a plane wave front incident at the interface of the two media gets refracted when it propagates from a rarer to a denser medium. Hence verify Snell’s law of refraction.
(b) When monochromatic light travels from a rarer to a denser medium, explain the following, giving reasons :
(i) Is the frequency of reflected and refracted light same as the frequency of incident light?
(ii) Does the decrease in speed imply a reduction in the energy carried by light wave?
Answer : (a) A compound microscope consists of two convex lenses parallel separated by some distance. The lens nearer to the object is called the objective. The lens through which the final image is viewed is called the eyepiece.
Magnifying power, when final image is at infinity : The magnification produced by the compound microscope is the product of the magnifications produced by the eyepiece and objective.
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(b) (i) Nearsightedness or Myopia s A person suffering from myopia can see only nearer objects clearly, but cannot see the objects beyond a certain distance clearly.
Myopic eye:
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Correction : To correct the eye from this defect, a concave lens of appropriate focal length is positioned close to the eye so that the parallel ray of light from an object at infinity after refraction through the lens appears to come from the far point P’ of the myopic eye.
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(ii) Farsightedness Or Hypermetropia : A person suffering from hypermetropia can see distant objects clearly, but cannot see nearer objects.
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Correction : To correct this defect, a convex lens of suitable focal length is positioned close to the eye so that the rays of light from an object placed at the point N after refraction through the lens appear to come from the near point N’ of the hypermetropic eye.
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-35
OR
(a) Hyugens Principle:

  • Each point on the primary wave front acts as a source of secondary wavelets,- transferring out disturbance in all directions in the same way as the original source of light does.
  • The new position of the wave front at any instant is the envelope of the secondary wavelets at that instant. Refraction on the basis of wave theory
  • Consider any point Q on the incident wave front.
  • Suppose when disturbance from point P on incident wave
    front reaches point P’ on the refracted wave front, the disturbance from point Q reaches Q’ on the refracting surface XY.
    cbse-previous-year-solved-papers-class-12-physics-delhi-2013-36

Since P’ A’ represents the refracted wave front, the time taken by light to travel from a point on incident wave front to the corresponding point on refracted wave front should always be the same. Now, time taken by light to go from Q to Q’ will be
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-37
The rays from different points on the incident wave front will take the same time to reach the corresponding points on the refracted wave front i.e. given equation (iv) is independent of AK. It will happen so, if
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-38
This is the Snell’s law for refraction of light.
(b) (i) The frequency of reflected and refracted light remains constant as the frequency of incident light because frequency only depends on the source of light.
(ii) Since the frequency remains same, hence there is no reduction in energy.

Question.28. (a). State the working principle of a potentiometer. With the help of the circuit diagram, explain how a potentiometer is used to compare the emfs of two primary cells. Obtain the required expression used for comparing the emfs.
(b) Write two possible causes for one sided deflection in a potentiometer experiment.
OR
(a) State Kirchhoff’s rules for an electric network. Using Kirchhoff’s rules, obtain the balance condition in terms of the resistance of four arms of Wheatstone bridge.
(b) In the meter bridge experimental set up, shown in the figure, the null point ‘D’ is obtained at a distance of 40 cm from end A of the meter bridge wire. If a resistance of 10 Ω is connected in series with R1, null point is obtained at AD = 60 cm. Calculate the values of R1 and R2.
Answer : (a) Working principle of Potentiometer : When a constant current is passed through a wire of uniform area of cross-section, the potential drop across any portion of the wire is directly proportional to the length of that portion.
Applications of Potentiometer for comparing emfs of two cells : The following figure stows an application of the potentiometer to compare the emf of two cells of emf E1 and E2
E1, Eare the emf of the two cells.
1, 2, 3 form a two way key.
When 1 and 3 are connected, E1 is connected to the galvanometer (G).
Jokey is moved to N1, which is at a distance Li from A, to find the balancing length.
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E1/E2 =l1/l2
Thus, we can compare the emfs of any two sources. Generally, one of the cells is chosen as a standard cell whose emf is known to a high degree of accuracy. The emf of the other cell is then calculated from equation (3).
(b) (i) The emf of the cell connected in main circuit may not be more than the emf of the primary cells whose emfs are to be compared.
(ii) The positive ends of all cells are not connected to the same end of the wire.
OR
(a) Kirchhoff’s First Law – Junction Rule : The algebraic sum of the currents meeting at a point in an electrical circuit is always zero.
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Kirchhoff’s Second Law – Loop Rule : In a closed loop, the algebraic sum of the emfs is equal to the algebraic sum of the products of the resistance and current flowing through them.
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Wheatstone Bridge is an arrangement of four resistances as shown in the following figure.
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This is the required balanced condition of Wheatstone Bridge, (b) Considering both the situations and writing them in the form of equations Let R’ be the resistance per unit length of the potential meter wire,
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-43

Question.29. (a) Derive the expression for the torque on a rectangular current carrying loop suspended in a uniform magnetic field. 
(b) A proton and a deuteron having equal momenta enter in a region of a uniform magnetic field at right angle to the direction of a the field. Depict their trajectories in the field.
OR
(a) A small compass needle of magnetic moment ‘tn is free to turn about an axis perpendicular to the direction of uniform magnetic field ‘B’. The moment of inertia of the needle about the axis is T. The needle is slightly disturbed from its stable position and then released. Prove that it executes simple harmonic motion. Hence deduce the expression for its time period.
(b) A compass needle, free to turn in a vertical plane orients itself with its axis vertical at a certain place on the earth. Find out the values of (i) horizontal component of earth s magnetic field and (ii) angle of dip at the place.
Answer: (a) Consider a rectangular loop-ABCD carrying current I.
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-44
Case I : The rectangular loop is placed such that the uniform magnetic field B is in the plane of loop.
No force is exerted by the magnetic field on the arms AD and BC. Magnetic field exerts a force F1 on arm AB.
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If there are V such turns the torque will be nlAB
Where, b —> Breadth of the rectangular coil
a —> Length of the rectangular coil
A = ab —> Area of the coil .
Case II: Plane of the loop is not along the magnetic field, but makes angle with it.
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SET II

Note : Except for the following questions, all the remaining questions have been asked in Previous Set.

Question.1. A cell of emf‘E’ and internal distance V draws a current
‘I’. Write the relation between terminal voltage ‘V’ in terms of E, I, r.
Answer : When the current I draws from a cell of emf E and internal resistance r, then the terminal voltage is V = E – Ir

Question.2. Which of the following substances are diamagnetic?
Bi, Al, Na, Cu, Ca and Ni
Answer : Bi and Cu are diamagnetic substances.

Question.3. A heating element is marked 210 V, 630 W. What is the value of current drawn by the element when connected to a 210 V  dc source?
Answer: In dc source, P = VI
Given that P = 630 Wand V = 210 V
So, I=P/V =630/210 =3 A

Question.10. An ammeter of resistance 1 Ω can measure current up to 1.0 A. (i) What must be the value of the shunt resistance to enable the ammeter to measure up to 5.0 A ? (ii) What is the combination resistance of the ammeter and the shunt?
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-51
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Question.14. A convex lens of focal length 20 cm is placed co axially in contact with a concave lens of focal length 25 cm. Determine the power of the combination. Will the system be converging or diverging in nature?
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-53
The focal length of the combination = 1 m = 100 cm As the focal length is positive, the system will be converging in nature.

Question.15. Using Bohr’s postulates, obtain the expressions for (i) kinetic energy and (ii) potential energy of the electron in stationary state of hydrogen atom.
Draw the energy level diagram showing how the transitions between energy levels result in the appearance of Lyman series.
Answer: According to Bohr’s postulates, in a hydrogen atom, a single electron revolves around a nucleus of charge +ke. For an electron moving with a uniform speed in a circular orbit or a given radius, the centripetal force is provided by Coulomb force of attraction between the electron and the nucleus. The gravitational attraction may be neglected as the mass of electron and proton is very small.
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-54
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Question.22. Figure shows a rectangular loop conducting PQRS in which the arm PQ is free to move. A uniform magnetic field acts in the direction perpendicular to the plane of the loop. Arm PQ is moved with a velocity v towards the arm RrS Assuming that the arms QR, RS and SP have negligible resistances and the moving arm PQ has the resistance r, obtain the expression for (i) the current in the loop (ii) the force and (iii) the power required to move the arm PQ.
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Question.23. Distinguish between ‘sky waves’ and ‘space waves’ modes of propagation in communication system.
(a) Why is sky wave mode propagation restricted to frequencies up to 40 MHz?
(b) Give two examples where space wave mode of propagation is used.
Answer : Sky wave : Sky waves are the AM radio waves, which are received after being reflected from the ionosphere. The propagation of radio wave signals from one point to another via reflection from ionosphere, is known as sky wave propagation. The sky wave propagation is an important consequence of the total internal reflection of radio waves. As we go higher in the ionosphere, there is an increase in the free electron density. Consequendy there is a decresise of refractive index. Thus, as a radio wave travels up in the ionosphere, it finds itself travelling from denser to rarer medium. It continuously bends away from its path till it suffers total internal reflection to reach back the Earth.
Space waves : Space waves are the waves which are used for satellite communication and line of sight path. The waves have frequencies up to 40 MHz provides essential communication and limited the line of sight paths.
(a) The e.m. waves of frequencies greater than 40 MHz penetrate the ionosphere and escape so, the sky wave propagation is restricted to the frequencies up to 40 MHz.
(b) In television broadcast and satellite communication, the space wave mode of propagation is used.

SET III

Note : Except for the following questions, all the remaining questions have been asked in Previous Set.

Question.6. A 5 V battery of negligible internal resistance is connected across a 200V battery and a resistance of 39 Ω as shown in the figure. Find the value of the current.
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-59

Question.7. Which of the following substances are para-magnetic? Bi, Al, Cu, Ca, Pb, Ni
Answer : Paramagnetic substances are Aluminium (Al) and Calcium (Ca).

Question.9. An ammeter of resistance 0.6 Q can measure current up to 1.0 A. Calculate (i) The shunt resistance required to enable the ammeter to measure current up to 5.0 A (ii) The combined resistance of the ammeter and the shunt.
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Question.15. A convex lens of focal length 30 cm is placed coaxially in contact with a concave lens? of focal length 40 cm. Determine the power of the combination. Will the system be converging or diverging in naituire?
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-62
The focal length of combination = 1.2 m = 120 cm
As the focal length is positive the system will be converging in nature.

Question.18. A capacitor of unknown capacitance is connected across a battery of v volts. The charge stored in it is 300 μc. When potential across the capacitor is reduced by 100 V, the charge stored in it becomes 100 μC. Calculate the potential V and , the unknown capacitance. What will be the charge stored in the capacitor if the voltage applied had increased by 100 V?
OR
A hollow cylindrical box of length 0.5 m and area of cross-section 20 cm is placed in a three-dimensional coordinate system as shown in the figure. The electric field in the region is given by E = 20 xi, where E is NC-1 and x is in meters. Find
(i) Net flux through the cylinder
(ii) Charge enclosed in the cylinder.
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Question.19. (a) Write two characteristic features distinguishing the diffraction pattern from the interference fringes obtained in Young’s double slit experiment.
(b) Two wavelength of sodium light 590 nm and 596 nm are used, in turn, to study the diffraction taking place due to a single slit of aperture 1 x 10-4 m. The distance between the slit and the screen is 1.8 m. Calculate the separation between the positions of the first maxima of the diffraction pattern obtained in the two cases.
Answer: (a) Two characteristic features distinguishing the diffraction pattern from the interference fringes obtained in Young’s double slit experiment are :
(i) The interference fringes may or may not be of the same width whereas the fringes of diffraction pattern are always of varying width.
(ii) In interference the bright fringes are of same intensity whereas in diffraction patten the intensity falls as we go to successive maxima away from the centre, on either side.
(b) Wavelength of the light beam, λ1 = 590 nm = 5.9 x 10-7 m
Wavelength of another light beam, λ2 = 596 nm = 5.96 x 10-7 m
Distance of the slits from the screen = D = 1.8 m
Distance between the two slits =1 x 10-4 m
For the first secondary maxima,
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Question.21. (a) In a nuclear reaction
cbse-previous-year-solved-papers-class-12-physics-delhi-2013-68
though the number of nucleons is conserved on both sides of the reaction, y et the energy is released. How? Explain.
(b) Draw a plot of potential energy between a pair of nucleons as a function of their separation. Mark the regions where potential energy is (i) positive and (ii) negative.
Answer : (a) ’In a nuclear reaction, the sum of the masses of the target nucleus \(_{ 2 }^{ 3 }{ He }\) may be greater or less the sum of the masses of tine product nucleus \(_{ 4 }^{ 2 }{ He }\) and the \(_{ 1 }^{ 1 }{ H }\) . So from the law of conservation of mass energy some energy (12.86 MeV) is evolved in nuclear reaction. This energy is called Q-value of the nuclear reaction. The binding energy of the nuclear reaction. The binding energy of the nucleus on the left side is not equal to the right side. The difference in the binding energies on two sides appearance energy released or absorbed in the nuclear reaction.
(b) Th e potential energy is minimum at ro : For distance larger than ro the negative potential energy goes on decreasing and for the distances less than ro the negative potential energy decrease to zero and then becomes positive and increases abruptly. Thus, A t o B is the positive potential energy region and B to C is the negative potential energy region.
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Question.25. (b) What is the significance of negative sign in the expression for the energy?
(c) Draw the energy level diagram showing how the line spectra corresponding to Paschen series occur due to transition between energy levels.
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SAIL Pivot Point Calculator

Diary Writing Format For Class 10 Topics, Examples

Diary Writing Format For Class 10 Topics, Examples

Diary Writing Format For Class 10 Topics, Examples

Diary Writing Topics And Examples:

1. A Day in Your Life: Describe a typical day in your life, from morning to night.
2. A Special Event: Write about a special event that you attended or participated in, such as a wedding, concert, or festival.
3. A Memorable Trip: Describe a memorable trip you took, including where you went, what you did, and what you learned.
4. A Challenge You Overcame: Write about a challenge you faced and how you overcame it. This could be anything from a difficult exam to a personal struggle.
5. A New Experience: Describe a new experience you had, such as trying a new food or learning a new skill.
6. A Favorite Memory: Write about a favorite memory from your childhood or teenage years.
7. A Goal You Achieved: Write about a goal you set for yourself and how you achieved it.
8. A Difficult Decision: Describe a difficult decision you had to make and how you came to your decision.
9. A Day without Technology: Write about a day when you disconnected from technology and how it made you feel.
10. A Random Act of Kindness: Describe a time when someone did something kind for you or when you did something kind for someone else.

Also Read: Diary Writing For Class 9

Example 1:

Dear Diary,

Today was a day when I challenged myself to step outside of my comfort zone. I decided to attend a dance class with a new instructor who is known for being tough, but I was determined to learn something new.

The class was harder than I expected, but I loved the challenge. The instructor pushed us to our limits, and I felt like I was learning so much. Even though my body was sore and tired, I couldn’t wait for the next class.

After dance class, I went to a café to write in my journal and read a book. I decided to try a new drink that the barista recommended, and it was surprisingly delicious. It was nice to enjoy something new and different.

In the evening, I volunteered at a local animal shelter. I love animals, and it was so rewarding to help out and spend time with the animals. I played with the kittens, walked the dogs, and cleaned up the cages. It was a lot of work, but it made me feel good to give back to the community.

Overall, today was a day of new experiences and challenges. I learned a lot, tried new things, and gave back to the community. I’m proud of myself for stepping outside of my comfort zone and pushing myself to be better.

Yours truly,
[Your Name]

Diary Writing Topics And Examples

Example 2:

Dear Diary,

Today was an eventful day. I woke up early in the morning and got ready for school. The day started with an English exam, which I had been preparing for weeks. I think I did well in the exam, but I’m not completely sure.

After the exam, we had a Math class, which was quite difficult. I had a hard time understanding some of the concepts, but my teacher was patient and explained them to me. I think I will have to study harder for the upcoming Math exam.

During the lunch break, I hung out with my friends. We talked about our plans for the weekend and our upcoming vacations. It was nice to take a break from studying and just relax with my friends.

After lunch, we had a Science class. We did an experiment on the properties of water. It was interesting to see how water can change its state from liquid to gas to solid. I enjoyed the practical aspect of the class.

In the evening, I attended my dance class. I am learning a new style of dance, and it’s quite challenging. But I love the feeling of accomplishment when I get a move right. I think I am slowly improving.

After dance class, I came home and had dinner with my family. We talked about our day and what we did. It was nice to catch up with them and share our experiences.

Overall, today was a good day. I learned a lot in school and had fun with my friends and family. I am looking forward to tomorrow and what it will bring.

Yours truly,
[Your Name]

Example 3:

Dear Diary,

Today was a difficult day. I woke up feeling tired and unmotivated. I had a headache and didn’t feel like going to school. But I knew I had to go, so I got ready and went to school.

The day started with a History class. We were learning about World War II, which is a difficult and emotional topic. I found myself getting upset and overwhelmed by the stories of the soldiers and the atrocities that occurred during the war.

After History, we had a Chemistry class. I had a hard time concentrating and understanding the concepts. My mind kept wandering, and I couldn’t focus on the lesson.

During the lunch break, I didn’t feel like talking to anyone. I just wanted to be alone and clear my head. I went to the library and read a book for a while.

After lunch, we had a Physics class. I found the class to be boring, and I couldn’t wait for it to be over.

In the evening, I went for a run to clear my head. Running always makes me feel better, and today was no exception. I felt refreshed and rejuvenated after my run.

After dinner, I studied for my upcoming exams. I tried to focus, but my mind kept wandering. I felt frustrated and anxious about the exams.

Overall, today was a difficult day. I struggled with my emotions and concentration. But I know that tomorrow is a new day, and I can start fresh.

Yours truly,
[Your Name]

Conclusion

Each of these diary entries shows the power of journaling to document daily life, record important events, and reflect on personal growth. Diary writing can help us process our emotions, gain perspective on our experiences, and develop a deeper understanding of ourselves. By taking the time to write in a journal, we can improve our mental and emotional wellbeing and create a record of our lives that we can look back on with pride and appreciation.

Story Writing For Class 2 Format, Examples, Topics, Exercises

Story Writing For Class 2 Format, Examples, Topics, Exercises

Story Writing For Class 2 Format, Examples, Topics, Exercises

Format for Story Writing for Class 2 Students:

The format for story writing for Class 2 students should be simple and easy to understand. You can use the following format as a guideline:

1. Title: Start by giving your story a title that catches the reader’s attention.
2. Introduction: In the introduction, introduce the main characters, the setting, and the problem that the story will address.
3. Body: The body of the story is where the action takes place. This is where the problem is solved, and the story progresses. You can include dialogues, descriptions, and actions to make the story interesting.
4. Conclusion: The conclusion is where the story ends, and the problem is resolved. You can add a moral to the story to give it a deeper meaning.

Also Read: Story Writing For Class 6 

Examples of Story Writing for Class 2 Students:

Here are some examples of story writing for Class 2 students:

Example 1: The Lion and the Mouse

Title: The Lion and the Mouse

Introduction: Once upon a time, in a jungle, a mighty lion was sleeping under a tree. Suddenly, a tiny mouse accidentally woke him up by running across his nose.

Body: The lion was furious and decided to eat the mouse. But the mouse pleaded for mercy, promising to help the lion someday. The lion laughed at the mouse’s promise but let him go. A few days later, the lion got trapped in a hunter’s net, and the mouse heard his cries for help. The mouse gnawed at the ropes and freed the lion. The lion was grateful to the mouse and learned that even the smallest creatures can be helpful.

Conclusion: The lion and the mouse became friends, and the lion promised to protect the mouse from all harm. The moral of the story is that kindness is always rewarded.

Example 2: The Boy Who Cried, Wolf

Title: The Boy Who Cried, Wolf

Introduction: Once upon a time, in a small village, there was a boy who took care of his sheep. He was very mischievous and loved to play pranks on the villagers.

Body: One day, the boy got bored and decided to play a prank on the villagers. He cried out, “Wolf! Wolf! There’s a wolf!” The villagers rushed to his aid, but when they got there, they found no wolf. The boy laughed and repeated the prank a few more times. But one day, a real wolf came, and the boy cried for help. The villagers ignored him, thinking it was another prank, and the wolf killed all his sheep.

Conclusion: The boy learned his lesson and realized that lying has consequences. The moral of the story is that honesty is the best policy.

Examples of Story Writing for Class 2 Students

Topics for Story Writing for Class 2 Students:

Here are some topics for story writing for Class 2 students:

1. A day at the beach
2. My favorite animal
3. A visit to the zoo
4. A magical adventure
5. My best friend
6. A Day in the Park
7. A scary story
8. A day in the life of a superhero
9. A trip to outer space
10. My favorite holiday

Exercises for Story Writing for Class 2 Students:

Here are some exercises for story writing for Class 2 students:

1. Give the students a picture and ask them to write a story about it.
2. Ask the students to write a story in which they are the main character.
3. Give the students a list of characters, a setting, and a problem, and ask them to write a story using those elements.
4. Ask the students to write a story with a surprise ending.
5. Give the students a story starter and ask them to continue the story.
6. Ask the students to write a story using only 5 words, and challenge them to make it interesting.
7. Give the students a topic and ask them to write a story in 10 sentences or less.
8. Ask the students to write a story using only dialogue.
9. Give the students a story prompt and ask them to write a story from the perspective of a different character.
10. Ask the students to write a story with a moral at the end.

Conclusion On Story Writing For Class 2:

Story writing is an essential skill that children need to develop. It helps them to express their creativity, imagination, and thoughts. As a teacher, you can help your students to develop this skill by providing them with examples, topics, and exercises. Remember to keep the format simple and easy to understand, and encourage your students to be creative and have fun while writing their stories.

CBSE Class 9 Maths Lab Manual – Angle in a Semicircle, Major Segment, Minor Segment

CBSE Class 9 Maths Lab Manual – Angle in a Semicircle, Major Segment, Minor Segment

Objective
To verify that angle in a semicircle is a right angle, angle in a major segment is acute, angle in a minor segment is obtuse by paper folding.

Prerequisite Knowledge

  1. Concept of semicircle, major segment and minor segment
  2. Concept of right angle, acute angle and obtuse angle.

Materials Required
White sheet, glazed papers, compass, pencil, tracing paper

Procedure
Case I.

  1. Draw a circle of any radius with centre O on a glazed paper. Cut it and paste it on white paper.
  2. Fold the circle along the line passing through the centre O to get a diameter AB.
    CBSE Class 9 Maths Lab Manual – Angle in a Semicircle, Major Segment, Minor Segment 1
  3. Take any point P on circumference of the circle.
  4. Join AP and BP by paper folding to get ∠APB.
  5. Make two replicas of ∠APB with the help of tracing paper such that ∠A1P1B1 and ∠A2P2B2.
  6. Place two ∆A1P1B1 and ∆A2P2B2 such that ∠P1 and ∠P2 coincide each other [fig.(ii)].
    CBSE Class 9 Maths Lab Manual – Angle in a Semicircle, Major Segment, Minor Segment 2

We notice ∠A1P1B1 and ∠A2P2B2 form a linear pair.
∴ ∠A1P1B1 + ∠A2P2B2 = 180° (linear pair).
2∠APB = 180° (∠A1P1B1 and ∠A2P2B2 are replicas of ∠APB)
∴ ∠APB = 90°

Case II. For major segment:

  1. Cut a circle of any radius using glazed paper with centre O and paste it on a white paper.
  2. Make a chord AB by paper folding.
  3. Take a point Q on the major segment. Join QA and QB by paper folding.
  4. Draw and cut replica of ∠AQB.
  5. Place the replica of ∠AQB on the newly drawn, right angled ∆DEF such that side BQ falls on DE.
    CBSE Class 9 Maths Lab Manual – Angle in a Semicircle, Major Segment, Minor Segment 3
    CBSE Class 9 Maths Lab Manual – Angle in a Semicircle, Major Segment, Minor Segment 4
    CBSE Class 9 Maths Lab Manual – Angle in a Semicircle, Major Segment, Minor Segment 5
    ∴ ∠AQB < ∠DEF = 90°
    ∴ ∠AQB is acute.

Case III. For minor segment:

  1. Cut a circle of any radius using glazed paper with centre O. Paste it on white paper.
  2. Make a chord AB by paper folding.
  3. Take any point M on the minor segment. Join MA and MB by paper folding to get ∠AMB.
  4. Draw and cut replica of ∠AMB with the help of tracing paper.
  5. Place the replica of ∠AMB on the base of newly drawn right angled triangle ∆DEF, such that base MB coincides with EF and point M coincides with E.
    CBSE Class 9 Maths Lab Manual – Angle in a Semicircle, Major Segment, Minor Segment 6
    CBSE Class 9 Maths Lab Manual – Angle in a Semicircle, Major Segment, Minor Segment 7
    Here, ∠AMB > ∠DEF = 90°
    ∴ ∠AMB is an obtuse angle.

Observation
We observe that
In Case I, AOB is a diameter and ∠APB is of 90°.
In Case II, AQB is a major segment and ∠AQB is an acute angle.
In Case III, AMB is a minor segment and ∠AMB is an obtuse angle.

Result
By paper folding method, we verified that angle in a semicircle is right angle. In any circle, angle in minor segment is obtuse angle, angle in major segment is an acute angle.

Learning Outcome
In any circle, any angle in a minor segment is always obtuse, any angle in a major segment is always acute, angle in semicircle is always a right angle.

Activity Time
Divide the circle into two parts:

  1. Along the diameter and measure different angles formed on the diameter by paper folding method.
  2. Along any chord (other than diameter) and measure the different angles formed by paper folding on two different segments.

Viva Voce

Question 1.
What is a semicircle ?
Answer:
Half of the circle.

Question 2.
If AB is any chord of a circle, what will be the sum of the angle in minor segment and major segment ?
Answer:
180°.

Question 3.
A circle has finite number of equal chords. Is this statement true.
Answer:
False.

Question 4.
What type of angle is obtained in minor segment ?
Answer:
Obtuse angle.

Question 5.
What type of angle is obtained in major segment?
Answer:
Acute angle.

Question 6.
What is the longest chord in a circle ?
Answer:
Diameter.

Question 7.
If the angle subtended by a chord in major segment is acute angle what will be angle at the centre ?
Answer:
Angle will be less than 180°.

Question 8.
If angle subtended by an arc is 70° in alternate segment, in which segment angle will lie ?
Answer:
It will lie in a major segment.

Question 9.
If the angle subtended by an arc is 110° in alternate segment, in which segment angle will lie ?
Answer:
It will lie in a minor segment.

Multiple Choice Questions

Question 1.
If two equal chords AB and CD intersect each other inside the circle at E. Then, arc AD and arc CD are:
(i) congruent
(ii) not-congruent
(iii) \(\widehat { AD }\) = 2\(\widehat { CB }\)
(iv) none of these

Question 2.
In any circle, measure of angle in minor segment is 110°, what is value of its opposite angle on the circle:
(i) 70°
(ii) 60°
(iii) 55°
(iv) none of these

Question 3.
In any circle, for a chord, the sum of opposite angles subtended by it in major segment and minor segment is:
(i) 180°
(ii) 360°
(iii) 90°
(iv) none of these

Question 4.
AB is a chord of a circle with centre O. OP = 3 cm if radius is 5 cm, OP ⊥ AB, then length of the chord AB will be:
(i) 8 cm
(ii) 4 cm
(iii) 16 cm
(iv) none of these

Question 5.
On a semicircle with AB as diameter, a point C is taken so that ∠CAB = 30°. Find ∠ACB:
(a) 30°
(ii) 60°
(iii) 90°
(iv) none of these

Question 6.
On a semicircle with PQ as diameter, a point B is taken so that ∠BPQ = 60°. Find ∠BQP:
(i) 30°
(ii) 90°
(iii) 120°
(iv) none of these

Question 7.
PQ and RS are two parallel chords of a circle and lines RP and SQ intersect each other at O outside the circle. Then, OP and OQ are:
(i) equal
(ii) not equal
(iii) OP = 3OQ
(iv) none of these

Question 8.
Find the area of a right angled triangle, if the radius of its circumcircle is 3 cm and altitude drawn to the hypotenuse is 2 cm:
(i) 3 cm2
(ii) 6 cm2
(iii) 2 cm2
(iv) none of these

Question 9.
If the angle in major segment is acute, then angle opposite to it will be:
(i) Obtuse
(ii) right angle
(iii) acute
(iv) none of these

Question 10.
If the angle in minor segment is obtuse then other angle on the same segment will be:
(i) right angle
(ii) acute
(iii) obutse
(iv) none of these

Answers

  1. (i)
  2. (i)
  3. (i)
  4. (i)
  5. (iii)
  6. (i)
  7. (i)
  8. (ii)
  9. (i)
  10. (iii)

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